b^2=1/25

Solution for b^2=1/25 equation:

b^2=1/25

We move all terms to the left:

b^2-(1/25)=0

We add all the numbers together, and all the variables

b^2-(+1/25)=0

We get rid of parentheses

b^2-1/25=0

We multiply all the terms by the denominator


b^2*25-1=0

Wy multiply elements

25b^2-1=0

a = 25; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·25·(-1)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10}{2*25}=\frac{-10}{50}
=-1/5
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10}{2*25}=\frac{10}{50}
=1/5
$